코딩 테스트 준비
숨박꼭질 3 - 골드 5 (백준, BFS)
개발쉐발
2023. 1. 19. 15:38
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from collections import deque
def bfs(start):
q = deque()
q.append(start)
arr[start] = 0
while q:
x = q.popleft()
if x == K:
return arr[x]
for nx in (x*2, x+1, x-1):
if 0 <= nx < 100001 and arr[nx] == -1:
if nx == x*2:
arr[nx] = arr[x]
q.appendleft(nx)
else:
arr[nx] = arr[x] + 1
q.append(nx)
N, K = map(int, input().split())
arr = [-1] * 100001
print(bfs(N))
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